SOLVED: Given:public class Test { private int sum; public int compute() { int x = 0 ...

Given:

public class Test {
	private int sum;
	public int compute() {
 		int x = 0;
 		while (x < 3) {
  			sum += ++x;
 		}
 		return sum / 4;
	}
	public static void main(String[] args) {
 		Test t = new Test();
 		int sum = t.compute();
 		sum = t.compute();
 		t.compute();
 		System.out.println(sum);
	}
}

What is the result?

An exception is thrown at runtime

6

3

9

Verified Answer

Correct Option - c

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Given:public class Test { private int sum; public int compute() { int x = 0; while (x < 3) { sum += ++x; } return sum / 4; } public static void main(String[] args) { Test t = new Test(); int sum = t.compute(); sum = t.compute(); t.compute(); System.out.println(sum); } }What is the result?

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Given:
`public class Test { private int sum; public int compute() { int x = 0; while (x < 3) { sum += ++x; } return sum / 4; } public static void main(String[] args) { Test t = new Test(); int sum = t.compute(); sum = t.compute(); t.compute(); System.out.println(sum); } }`
What is the result?