SOLVED: What is the output of the following Python code?class A(): def __init__(self, ...

What is the output of the following Python code?

class A():
  def __init__(self, a={}):
    if not ('1' in a):
        a['1'] = 1
    else:
        a['1'] += 1
    print(a['1'])

for i in range(2):
    a = A()

1 2

1 1

1

2

Verified Answer

Correct Option - a

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What is the output of the following Python code?class A(): def __init__(self, a={}): if not ('1' in a): a['1'] = 1 else: a['1'] += 1 print(a['1']) for i in range(2): a = A()

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What is the output of the following Python code?
class A(): def init(self, a={}): if not ('1' in a): a['1'] = 1 else: a['1'] += 1 print(a['1']) for i in range(2): a = A()