Predict the output of the following code.

#!/bin/bash

name="Hans"

case `test $name == "hans"` in

0) echo "The name is Hans";;

1) echo "The name is not Hans";;

*) echo "The name is not known;;

esac

The name is not Hans

The name is Hans

The name is not known

test expression cannot be used with case statement

Verified Answer
Correct Option - c

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